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Examsci
Scientific Study - Group B (Very Short Questions) [1 Mark]
1. (2081 Koshi Q.No. 2a)
Dependent variable: Solubility of salt.
2. What is the dependent variable in throwing a stone with a stretched rubber band?
Answer: Distance travelled by the stone.
3. Write the fundamental units included in the unit of force.
Answer: Kilogram (kg), metre (m) and second (s).
4. Write a difference between fundamental unit and derived unit.
Answer: Fundamental units are independent, whereas derived units are formed from fundamental
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1. The title of the article/ text |
The title of the article (text) is … The title of the article (text) under consideration is The text is head-lined… The head-line of the article I've read is …. |
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2. The author of the article/ text: where and when the article/ text was published |
The author of the article/ text is … The article/ text is written by … It is (was) published in … It is (was) |
ERGWRET
1. Define GCD. (1 Mark)
GCD (Greatest Common Divisor) is the largest positive integer that divides two or more integers exactly.
2. Find the prime factorization of 1330. (1 Mark)
1330=2×5×7×19
3. Define Residue. (1 Mark)
A residue modulo mmm is any integer equivalent to another integer modulo mmm.
4. State the Chinese Remainder Theorem. (1 Mark)
If the moduli are pairwise coprime, a system of congruences has a unique solution modulo the product of the moduli.
5. Define Fermat Numbers.
Web Tech
JAVASCRIPT: 1. JS is a fast-growing language, with a LOT of features being added to every release! JSONP, arrow functions, arguments, call arguments, rest, blob 'DOMString', a 'download' button, apply() vs call(). 1. JSONP (JSON with Padding), which was a technique used before modern CORS support to get data from another website. JSONP (JavaScript Object Notation with Padding) is an older technique used to retrieve data from a server when normal AJAX requests using XMLHttpRequest (XHR) or fetch(
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9. A researcher wants to know the intelligence of students in a school. He selected two groups of students. In the first group there 150 students having mean IQ of 75 with a S.D. of 15 in the second group there are 250 students having mean IQ of 70 with S.D. of 20. Is there a significant difference between the means of two groups ?
Solution
Given
For Group I:
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Sample size,
n1=150n1=150
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Sample mean,
xˉ1=75xˉ1=75
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Standard deviation,
s1=15s1=15
For Group II:
-
Sample size,
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The marks obtained in Statistics in a certain examination found to be normally distributed. If 15% of the students ≥ 60 marks, 40% < 30 marks, find the mean and standard deviation?
where μμ is the mean and σσ is the standard deviation.
Given
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P(X≥60)=0.15P(X≥60)=0.15
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P(X<30)=0.40P(X<30)=0.40
We need to find μμ and σσ.
Step 1: Convert to Z-values
(i) P(X≥60)=0.15P(X≥60)=0.15
Hence,
P(X<60)=0.85P(X<60)=0.85
From the standard normal table,
P(Z<1.04)
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11. Calculate the coefficient of correlation from the following data
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X |
12 |
9 |
8 |
10 |
11 |
13 |
7 |
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Y |
14 |
8 |
6 |
9 |
11 |
12 |
3 |
Step 3: Substitute into the for
To calculate the Karl Pearson's coefficient of correlation (r):
The formula is:
r=∑dx dy∑dx2×∑dy2r=∑dx2×∑dy2∑dxdy
where:
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dx=X−Xˉdx=X−Xˉ
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dy=Y−Yˉdy=Y−Yˉ
Step 1: Find the means
Xˉ=12+9+8+10+11+13+77=707=10Xˉ=712+9+8+10+11+13+7=770=10Yˉ=14+8+6+9+11+12+37=637=9Yˉ=714+8+6+
Respiratory chest X-rays interpretation
1. Pleural effusion -
Interpretation-
Quality- RIPE- good
1. Airways- trachea deviated to the right (pushing effect- because of effusion); cannot visualise the carina or bronchus
2. Breathing- effusion in the left lower and middle zones which end in the upper zone with a meniscus sign; lung markings present throughout the right lung
3. Cardiac- cannot assess the size, difficult to visualise left heart borders
4. Diaphragm- right hemidiaphragm can be seen; left - cannot be seen, blunting of
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Find the GCD OF (143,227)?
The Euclidean Algorithm is used to find the Greatest Common Divisor (GCD) of two integers by repeatedly dividing the larger number by the smaller number until the remainder becomes 0.
Step 1:
227=143×1+84227 = 143 \times 1 + 84227=143×1+84
Step 2:
143=84×1+59143 = 84 \times 1 + 59143=84×1+59
Step 3:
84=59×1+2584 = 59 \times 1 + 2584=59×1+25
Step 4:
59=25×2+959 = 25 \times 2 + 959=25×2+9
Step 5:
25=9×2+725 = 9 \times 2 + 725=9×2+7
Step 6:
9=7×1+29 = 7 \times